ii6ri6r 2021-04-18 18:00 采纳率: 100%
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一个Python的GUI为什么出错?

from tkinter import *
import random
from math import *
from tkinter import messagebox

from pefile import b


class Application(Frame):

    def __init__(self, master=None):
        super().__init__(master)
        self.master = master
        self.pack()
        self.createWidget()

    def createWidget(self):
        a = StringVar()
        b = StringVar()
        c = StringVar()
        
        self.label01 = Label(self, text="二次项系数:").grid(row=0, column=0)
        self.entry01 = Entry(self, textvariable=a).grid(row=0, column=1)

        self.label02 = Label(self, text="一次项系数:").grid(row=1, column=0)
        self.entry02 = Entry(self, textvariable=b).grid(row=1, column=1)
        
        self.label03 = Label(self, text="常数项系数:").grid(row=2, column=0)
        self.entry03 = Entry(self, textvariable=c).grid(row=2, column=1)

        Button(self, text="计算", command=self.jisuan).grid(row=3, column=1, sticky=EW)
        Button(self, text="退出").grid(row=3, column=2, sticky=E)

        self.label04 = Label(self, text="请先将方程的右端化为0").grid(row=4, sticky=EW)
    
    def jisuan(self):
        aa = self.label01.get()
        bb = self.label01.get()
        cc = self.label01.get()
        print(aa)
        d = int((bb)**2-4*(aa)*(cc))
        if d < 0:
            messagebox.showinfo("计算结果","此二次方程无实数根")
        elif d == 0:
            outcome = -b/(2*aa)
            messagebox.showinfo("计算结果","方程有且仅有一个实数根:%d" % outcome)
        elif d > 0:
            x1 = (-b + sqrt(d))/(2*aa)
            x2 = (-b - sqrt(d))/(2*aa)
            messagebox.showinfo("计算结果","方程有两个实数根,分别为:%d和%d" % (x1, x2))



if __name__=='__main__':
    root=Tk()
    root.geometry("400x300+200+300")
    app=Application(master=root)
    root.mainloop()


input()
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  • CSDN专家-HGJ 2021-04-18 18:34
    关注

    改了一下代码,界面运行正常,排除了代码中错误,但是其计算部分你看一下再作调整。

    from tkinter import *
    import random
    from math import *
    from tkinter import messagebox
    
    #from pefile import b
    
    
    class Application(Frame):
    
        def __init__(self, master=None):
            super().__init__(master)
            self.master = master
            self.pack()
            self.createWidget()
    
        def createWidget(self):
            a = StringVar()
            b = StringVar()
            c = StringVar()
    
            self.label01 = Label(self, text="二次项系数:").grid(row=0, column=0)
            self.entry01 = Entry(self, textvariable=a)
            self.entry01.grid(row=0, column=1)
    
            self.label02 = Label(self, text="一次项系数:").grid(row=1, column=0)
            self.entry02 = Entry(self, textvariable=b)
            self.entry02.grid(row=1, column=1)
    
            self.label03 = Label(self, text="常数项系数:").grid(row=2, column=0)
            self.entry03 = Entry(self, textvariable=c)
            self.entry03.grid(row=2, column=1)
    
            Button(self, text="计算", command=self.jisuan).grid(
                row=3, column=1, sticky=EW)
            Button(self, text="退出",command=self.quit).grid(row=3, column=2, sticky=E)
    
            self.label04 = Label(self, text="请先将方程的右端化为0").grid(row=4, sticky=EW)
    
        def jisuan(self):
            aa = self.entry01.get()
            bb = self.entry02.get()
            cc = self.entry03.get()
            print(aa)
            d = float((int(bb)**2-4*(int(aa)*int(cc))))
            if d < 0:
                messagebox.showinfo("计算结果", "此二次方程无实数根")
            elif d == 0:
                outcome = -b/(2*aa)
                messagebox.showinfo("计算结果", "方程有且仅有一个实数根:%d" % outcome)
            elif d > 0:
                x1 = (-b + sqrt(d))/(2*aa)
                x2 = (-b - sqrt(d))/(2*aa)
                messagebox.showinfo("计算结果", "方程有两个实数根,分别为:%d和%d" % (x1, x2))
    
    
    if __name__ == '__main__':
        root = Tk()
        root.geometry("400x300+200+300")
        app = Application(master=root)
        root.mainloop()
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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