Integer.parseInt方法报错

Question

JTextField zggr = new JTextField();

int zg = Integer.parseInt(zggr.getText());

System.out.println(zg);

将zg的值打印出来显示正确，将异常捕捉程序运行正常，但依然报错

 

Answer 1

zggr.getText()获取到的是空值，改一下代码

if(zggr.getText() != null && !zggr.getText().equals(""){

           int zg = Integer.parseInt(zggr.getText().trim());

            System.out.println(zg);

}