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- benbenli 2021-05-16 20:07关注
a = [[1, 2, 5, 7], [4, 1, 8, 0], [2, 0, 5, 1], [0, 2, 1, 1]] n = int(len(a) / 2) s = [[0, 0], [0, 0]] for i in range(0, 2 * n): r = int(i/n) s[r][0] += sum(a[i][0:n]) s[r][1] += sum(a[i][n:2*n]) for i in range(0, 2): for j in range(0, 2): s[i][j] /= n * n print(s) # Output [[2.0, 5.0], [1.0, 2.0]]
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