random用float求80-100以内随机值

Question

编程模拟10位评委给选手打分，随机打分，去掉一个最大值和最小值，剩下的8个求平均值，即为选手的最终成绩，结果保留两位小数

Answer 1

import java.util.Scanner;
public class Test07 {
    public static void main(String[] args) {

        Random r = new Random();
        float[] score = new float[10];
        float sum = 0;

        // 遍历数组
        for (int i = 0; i < score.length; i++) {
            score[i] = 80+r.nextFloat(21);  //随机生成80-100的数
            System.out.print(score[i] + "\t");  // 打印生成的分数
        }

        float max = score[0];
        float min = score[0];

        // 找出最大值max和最小值min
        for (int i = 0; i < score.length; i++) {
            sum += score[i];
            if(score[i] > max){
                max = score[i];
            }else if(score[i] < min){
                min = score[i];
            }
        }
        

        float avg = (sum-max-min)/(score.length-2);
        System.out.println(String.format("%.2f", avg));
    }
}