救命

Question

救命

Answer 1

完整代码如下：

#include <iostream>
#include <list>
using namespace std;

int main()
{
	int ia[5]={1,2,3,4,5};
	list<int> lst1(ia,ia+5);
	list<int>::iterator iter1 = lst1.begin(),iter2 = lst1.end();
	for (iter2--;  ;iter2--)
	{
		int d = *iter2;
		printf("%d ",d);
		if( iter2 == iter1)
			break;
	}
	return 0;
}