import java.util.ArrayList;
public class App {
public static void main(String[] args) {
School school=new School("龙岗五联","深圳技师学院","123456789");
Banji class1=new Banji("1班","20180901","20220901");
Banji class2=new Banji("2班","20180901","20220901");
Banji class3=new Banji("3班","20180901","20220901");
Student s1=new Student("学生1",1,"123456789",18);
Student s2=new Student("学生2",2,"2457878989",18);
Student s3=new Student("学生3",1,"5678456543",18);
Student s4=new Student("学生4",2,"10086666666",18);
Student s5=new Student("学生5",1,"24578654689",18);
Student s6=new Student("学生6",2,"12589468467",18);
Student s7=new Student("学生7",1,"13854268765",18);
Student s8=new Student("学生8",2,"13864568745",18);
Student s9=new Student("学生9",1,"15886478687",18);
Student s10=new Student("学生10",2,"7568745687",18);
ArrayList<Banji> teamplist = new ArrayList<Banji>();
teamplist.add(class1);
teamplist.add(class2);
teamplist.add(class3);
school.setBanlist(teamplist);
ArrayList<Student> stlist1 = new ArrayList<Student>();
stlist1.add(s1);
stlist1.add(s2);
stlist1.add(s3);
class1.setStudentlist(stlist1);
ArrayList<Student> stlist2 = new ArrayList<Student>();
stlist2.add(s4);
stlist2.add(s5);
stlist2.add(s6);
class2.setStudentlist(stlist2);
ArrayList<Student> stlist3 = new ArrayList<Student>();
stlist3.add(s7);
stlist3.add(s8);
stlist3.add(s9);
stlist3.add(s10);
class3.setStudentlist(stlist3);
int qbrs = 0;
for (int i=0;i<school.getBanlist().size();i++){
Banji c1= school.getBanlist().get(i);
qbrs+=c1.getStudentlist().size();
}
if(Student.getsex()==1){
System.out.println("男");}
else{
System.out.println("女");
}
System.out.println("学校名是:"+school.getName()+"地址是"+school.getAddress()+"电话是:"+school.getTel()+"有"+qbrs+"名学生");
}
}
java 怎么在这下面的程序中学校判断学生的男生和女生各有多少名啊 好难
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5条回答 默认 最新
- 年轻的狼 2021-05-24 16:02关注
Integer peopleNum = 0; // 总人数 Integer boyNum = 0; // 男生人数 for(Banji banjiOne:teamplist){ for(Student studentOne: banjiOne) { if(studentOne.sex == 1){ boyNum ++; } } }
大概就是这样,女生人数就是总人数-男人数,sex换成你定义的对象属性就可以了
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