循环一个数组对象，根据对象中的某个值来判断下面代码，是否执行

Question

let a = false;
let b = [{ judge: 1 }, { judge: 3 }, { judge: 0 }]
for (let i = 0; i < b.length; i++)
{
    a = b[i].judge === 0;
}
if (a) return;

请教各位大佬还有跟好的方法吗

Answer 1

let b = [{ judge: 1 }, { judge: 3 }, { judge: 0 }]
if(b.findIndex((v, i)=>v.judge==0)) return;

那你可以这样写，通过判断数组里是否有等于0的，来return