python作业，，，，

Question

编写函数word（），统计各个单词出现的次数。编程思路：输入一段英文句子，如：“Please you listen to be or not to be to you”,转换为小写字母后，以空格分离出单词列表，统计相同单词出现的频率，然后产生字典项（键值对）列表如[('please', 1), ('you', 2), ('listen', 1), ('to', 3), ('be', 2), ('or', 1), ('not', 1)] ，再按列表各元素的第2项（值）用lambda降序排列，如[('to', 3), ('you', 2), ('be', 2), ('please', 1), ('listen', 1), ('or', 1), ('not', 1)] 。效果如下图所示。

救命啊。上课学完全忘了

Answer 1

data = "Please you listen to be or not to be to you"
tmp = [i.lower() for i in data.split(' ')]
total_word = {}
for i in tmp:
    if total_word.get(i, 0):
        total_word[i] += 1
    else:
        total_word[i] = 1
sort_total = sorted(total_word.items(), key=lambda x: x[1], reverse=True)
print(sort_total)

[('to', 3), ('you', 2), ('be', 2), ('please', 1), ('listen', 1), ('or', 1), ('not', 1)]