python一元二次方程求解

Question

 

Answer 1

import math
a = float(input("请输入a的值："))
b = float(input("请输入b的值："))
c = float(input("请输入c的值："))
if a==0 and b==0:
    print('Data error')
elif a==0 and b!=0:
    print(-1*c/b)
else:
    key = b**2-4*a*c
    if key < 0:
        print("该方程无实数解")
    elif key == 0:
        x = -b/(2*a)
        print(x)
    else :
        x1 = (-b+math.sqrt(key))/(2*a)
        x2 = (-b-math.sqrt(key))/(2*a)
        print(x1," ",x2)