1条回答 默认 最新
- qfl_sdu 2021-06-16 02:00关注
代码如下:如有帮助,请采纳一下,谢谢。
#include <stdio.h> #include <string.h> typedef struct candidate { char name[20]; int count; }CANDIDATE; int Election(CANDIDATE can[],int n,int elector) { int i,j; int feipiao = 0; char name[20] = {0}; //初始化投票人数,避免出现未初始化的情况 for (i = 0;i < n; i++) { can[i].count = 0; } //投票 for (i = 0;i < elector; i++) { printf("请投票人%d投票:",i+1); scanf("%s",name); for (j = 0; j < n;j++) { if(strcmp(can[j].name,name)==0) { can[j].count += 1; break; } } if(j == n) feipiao +=1; } return feipiao; } int main() { int fp = 0; int i = 0; CANDIDATE can[3]; strcpy(can[0].name , "li"); strcpy(can[1].name , "zhang"); strcpy(can[2].name , "wang"); fp = Election(can,3,10); printf("废票数:%d\n",fp); for (;i<3;i++) { printf("%s\t%d\n",can[i].name,can[i].count); } return 0; }
本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 1无用