用Python生成100个2位随机正整数，按每行十个输出

Question

用Python生成100个2位随机正整数，按每行十个输出，并求出个位数字分别为0,1,2,3,4,5,6,7,8,9的正整数的个数

Answer 1

可能有些繁琐，不过可以运行

import random as rd
number = []
for i in range(1,101):
    if i % 10 != 0:
        b = rd.randint(10,100)
        number.append(str(b))
        print(b,end = " ")
    else:
        b = rd.randint(10,100)
        number.append(str(b))
        print(b,end = "\n")
n = 0
for i in number:
    if int(i[1]) in range(0,10):
        n += 1

print(n)