xsgkaka 2013-03-03 21:45 采纳率: 0%
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spring mvc @sessionattributes @ResponseBody 公用报错

[code="java"]

@Controller
@RequestMapping("/user")
@SessionAttributes(LoginConstants.CURRENT_USER)
public class UserContorller {
private UserService userService;
public UserService getUserService() {
return userService;
}

@Autowired
public void setUserService(UserService userService) {
    this.userService = userService;
}

@ResponseBody
@RequestMapping( value="login" ,method=RequestMethod.GET)
public String login(LoginForm loginForm,ModelMap modelMap){
    UserEntity userEntity = new UserEntity();
    userEntity.setName(loginForm.getName());
    userEntity.setPassword(loginForm.getPassword());
    userEntity = userService.login(userEntity);
    if(null != userEntity){//登录成功
        modelMap.addAttribute(LoginConstants.CURRENT_USER, userEntity);
        return "ok";
    }else{//登录失败 
        return "error";
    }
}

}
[/code]

报错如下错误:
[code="java"]
严重: Servlet.service() for servlet springmvc threw exception
java.lang.IllegalStateException: Cannot create a session after the response has been committed
at org.apache.catalina.connector.Request.doGetSession(Request.java:2400)
at org.apache.catalina.connector.Request.getSession(Request.java:2120)
at org.apache.catalina.connector.RequestFacade.getSession(RequestFacade.java:833)
[/code]

  • 写回答

2条回答

  • z276356445t 2013-03-04 10:04
    关注

    @ResponseBody

    @RequestMapping( value="login" ,method=RequestMethod.GET)

    public String login(LoginForm loginForm,ModelMap modelMap){

    UserEntity userEntity = new UserEntity();

    userEntity.setName(loginForm.getName());

    userEntity.setPassword(loginForm.getPassword());

    userEntity = userService.login(userEntity);

    if(null != userEntity){//登录成功

    modelMap.addAttribute(LoginConstants.CURRENT_USER, userEntity);

    return "ok";

    }else{//登录失败

    return "error";

    }

    }
    请将方法的参数加上该为public String login(HttpSession session, LoginForm loginForm,ModelMap modelMap)

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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