c语言求解 求解 教一下

Question

 

Answer 1

用if...else就可以

#include <math.h>
void main()
{
    double x,y;
    scanf("%lf",&x);
    bool b = true;
    if(x>=-10 && x<=4)
        y = fabs(x-2);
    else if(x>=5 && x<=7)
        y = x+10;
    else if(x>=8 && x<=12)
        y = x*x*x*x;
    else
    {
        printf("NO answer);
        b = false;
    }
    if(b)
        printf("y=%.2lf",y);
}