yuriioo 2021-06-18 22:48 采纳率: 78.6%
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请问这道python怎么做呀?

 

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  • Roc-xb 后端领域优质创作者 2021-06-18 23:15
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    #!/usr/bin/python
    # -*- coding: UTF-8 -*-
    """
    @author: YangPC
    @time:2021/06/18
    @QQ:327844761
    @微信公众号:ewbang
    
    """
    import random
    import math
    
    
    # 随机数
    def sjs(n):
        return random.randint(1, n)
    
    
    # 平方数
    def pfs(n):
        a = int((math.sqrt(n)))
        return a * a == n
    
    
    # 第一题
    def fun1():
        ls1 = [sjs(10) ** 2 for i in range(5)]
        print(ls1)
    
    
    # 第二题
    
    def fun2():
        ls2 = [sjs(100) for i in range(10)]
        # 排序
        ls2.sort()
        print(ls2)
        return ls2
    
    
    # 第三题
    def fun3():
        ls3 = []
        for num in fun2():
            if pfs(num):
                ls3.append(num)
        print(ls3)
    
    
    # 第四题
    def fun4():
        ls4 = [sjs(100) for i in range(100)]
        count = 0
        for num in ls4:
            if pfs(num):
                count += 1
        print(count)
    
    
    if __name__ == '__main__':
        fun1()
        fun2()
        fun3()
        fun4()
    

    程序输出结果:回答不易,若有帮助,望采纳!

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