掷骰子游戏，谢谢各位大佬

Question

骰子游戏（作业）
编写程序模拟掷骰子游戏。已知掷骰子游戏的游戏规则为：每个骰子有6面，这些面包含1、2、3、4、5、6个点，投两枚骰子之后，计算点数之和。如果第一次投的点数和为7或11，则游戏者获胜；如果第一次投的点数和为2、3或12，则游戏者输；如果第一次投的点数和为4、5、6、8、9或10，则将这个和作为游戏者获胜需要掷出的点数，继续投骰子，直到赚到该点数时算是游戏者获胜。如果投掷7次仍未赚到该点数，则游戏者输。
验证结果如下

 

Answer 1

#include <stdio.h>
#include <time.h>
#include <stdlib.h>  

int CreateSocal()
{
    static int sran = 50;
    srand(time(NULL) + (sran+=50));
    int c = rand() % 6 + 1;
    return c;
}
int main()
{
    int gameover = 0;
    int c = CreateSocal();
    int c2 = CreateSocal();

    switch(c+c2)
    {
        case 7:
        case 11:
            gameover = 1;
            printf("Player rolled %d + %d = %d\nPlayer wins\n", c, c2, c + c2);
            break;
        case 2:
        case 3:
        case 12:
            gameover = 1;
            printf("Player rolled %d + %d = %d\nPlayer failed\n", c, c2, c + c2);
            break;
        default:
            printf("Player rolled %d + %d = %d\nPoint is %d\n", c, c2, c+c2, c+c2);
            break;
    }

    if (gameover == 1)
    {
        getchar();
        return 0;
    }

    int n = 0, n2 = 0;
    for (int i = 0; i < 7; i++)
    {
        n=CreateSocal();
        n2=CreateSocal();
        if ( (n + n2 ) == (c+c2))
        {
            printf("Player rolled %d + %d = %d\nPlayer wins\n", n, n2, n + n2);
            getchar();
            return 0;
        }
        else
        {
            printf("Player rolled %d + %d = %d\n", n, n2, n + n2);
        }
    }
    printf("Player failed\n");
    getchar();
    return 0;
}