bjyx1991 2021-06-21 10:07 采纳率: 66.7%
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这个程序是什么地方出了问题吗,运行不了

#include <stdio.h>

main()

{ char c1,c2;

   int i;

   FILE*fp1,*fp2;

   if ((fp1=fopen("E:\\f1.txt","w+"))==NULL)

   { printf("Can't open f1.txt.\n"); exit(0); }

      if((fp2=fopen("E:\\f2.txt","w"))==NULL;

   { printf("Can't open f2.txt\n");exit(0);}

   for (i=0;i<3;i++)

   { scanf("%c%*c",&c1); putc(c1,fp1); }

   for (i=0;i<3;i++)

   { scanf("%c%*c",&c2); putc(c2,fp2);}

   fputc(0xff,fp1);

   fclose(fp2);

      rewind(fp1);

   if((fp2=fopen("E:\\f2.txt","a"))==NULL)

   { printf("Can't open f2.txt.\n");exit(0); }

   while((c1=getc(fp1))!=EOF)

   { putc(c1,fp2); }

   fputc(0xff,fp2);

   fclose(fp2);

   fclose(fp1);

   printf("f2.txt file output : \n")

   fp2=fopen("E:\\f2.txt","r"):

   while((c1=getc(fp2))!=EOF) { printf("%c",c1); }

   printf("\n");

   flcose(fp2);

   system("pause");

   

 

}

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3条回答 默认 最新

  • shn_baby 2021-06-21 10:17
    关注
    main()
    {
    	char c1, c2;
    	int i;
    	FILE*fp1, *fp2;
    	if ((fp1 = fopen("E:\\f1.txt", "w+")) == NULL)
    	{
    		printf("Can't open f1.txt.\n"); 
    		exit(0);
    	}
    	if ((fp2 = fopen("E:\\f2.txt", "w")) == NULL)
    	{ 
    		printf("Can't open f2.txt\n"); 
    		exit(0); 
    	}
    	for (i = 0; i < 3; i++)
    	{
    		scanf("%c%*c", &c1); 
    		putc(c1, fp1);
    	}
    	for (i = 0; i < 3; i++)
    	{
    		scanf("%c%*c", &c2); 
    		putc(c2, fp2);
    	}
    	fputc(0xff, fp1);
    	fclose(fp2);
    	rewind(fp1);
    	if ((fp2 = fopen("E:\\f2.txt", "a")) == NULL)
    	{
    		printf("Can't open f2.txt.\n"); 
    		exit(0);
    	}
    	while ((c1 = getc(fp1)) != EOF)
    	{
    		putc(c1, fp2);
    	}
    	fputc(0xff, fp2);
    	fclose(fp2);
    	fclose(fp1);
    	printf("f2.txt file output : \n");
    	fp2 = fopen("E:\\f2.txt", "r");
    	while ((c1 = getc(fp2)) != EOF)
    	{ 
    		printf("%c", c1);
    	}
    	printf("\n");
    	fclose(fp2);
    	system("pause");
    
    }

    不确定是void main()还是main()

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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