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CSDN专家-Matlab_Fans 2021-06-30 21:29关注直接上代码吧
syms x y f = (6*x-x.^2) .* (4*y-y.^2); dfdx = diff(f,x); dfdy = diff(f,y); df2dx2 = diff(dfdx,x); df2dy2 = diff(dfdy,y); df2dxdy = diff(dfdx,y); [x0,y0] = solve(dfdx,dfdy); x = x0; y = y0; A = subs( df2dx2 ); B = subs( df2dxdy ); C = subs( df2dy2 ); delta = A.*C-B.^2; disp('极值点有 x:') disp( x(delta>0) ) disp('y:') disp( y(delta>0) )结果
极值点有 x = 3 y = 2本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 1无用