C语言，查找功能怎么写？

Question

求问如何改善查找功能达到输入姓名一部分，前部分后部分都可以找到有关的信息，而不相关的信息不会输出 以下是部分代码：

    int is_find=0;
    char find[NUM];
    //记录需要查找的内容,并作为查找成功与否的标识符
    printf("Please enter the name you want to find：");
    getchar();
    gets(find);
    for(int i=0;i<NUM;i++)
    {
        if(strcmp(stu[i].name,find)>=0)
        {
            printf("\nSearch success\n");
            printf("The student's student number is:%s\n",stu[i].id);
            printf("The student's name is:");
            printf("%s",stu[i].name);
            printf("\nThe student's scores in various subjects are\n");
            for(int c=0;c<3;c++)
            {
                printf("The result of the %d course is %.2f\n",c+1,stu[i].ach[c]);
            }
            printf("The student's total score is:%.2f",stu[i].sum);
            printf("\n");
            is_find=1;
        }
    }
    if(is_find!=1)
    {
        printf("There is no such person\n");
    }
    getch();

Answer 1

定义一个字符串查找函数，然后再if中调用就可以了，如下：

//判断字符串s是否包含字符串t
int isContain(char* s,char* t)
{
    char*p,*q;
    while(*s)
    {
        p = s;
        q = t;
        while(*q)
        {
            if(*p != *q)
                break;
            q++;
            p++;
        }
        if(*q=='\0')
            return 1;
        s++;
    }
    return 0;
}


//然后将if(strcmp(stu[i].name,find)>=0)，这句话改成：if(isContain(stu[i].name,find))
//下面是修改后的代码：
int is_find=0;
    char find[NUM];
    //记录需要查找的内容,并作为查找成功与否的标识符
    printf("Please enter the name you want to find：");
    getchar();
    gets(find);
    for(int i=0;i<NUM;i++)
    {
        if(isContain(stu[i].name,find))
        {
            printf("\nSearch success\n");
            printf("The student's student number is:%s\n",stu[i].id);
            printf("The student's name is:");
            printf("%s",stu[i].name);
            printf("\nThe student's scores in various subjects are\n");
            for(int c=0;c<3;c++)
            {
                printf("The result of the %d course is %.2f\n",c+1,stu[i].ach[c]);
            }
            printf("The student's total score is:%.2f",stu[i].sum);
            printf("\n");
            is_find=1;
        }
    }
    if(is_find!=1)
    {
        printf("There is no such person\n");
    }
    getch();