C语言100减去1/2n-1求值

Question

Answer 1

供参考：

#include<stdio.h>

int main()
{
    int n,i=1;
    double sum=100.0;
    scanf("%d",&n);
    while(i<=n)
    {
         sum -= (double)1/(2*i+1);
         i++;
    }
    printf("sum=%.2f\n",sum);
    
    return 0;
}