python爬取教师信息代码出现错误，哪里有问题呀

Question

import requests
from bs4 import BeautifulSoup
import xlwt
import re
def main():
    data_list=get_data(url_base)
    path='xw.tc'
    savedata(data_list,path)

find_link=re.compile(r"<a href='(.*?)'.* class='teac-name>")
find_name=re.compile(r"<a href=.*>(.*)</a>")
find_intro=re.compile(r"<p class='teac-zc'>(.*)</p>")



def get_data(url_base):
    data_list=[]
    html=ask_data(url_base)
    soup=BeautifulSoup(html,'html.parser')
    for item in soup.find_all('ul',style_='overflow:hidden;'):
        data=[]
        item=str(item)
        link=re.findall(find_link,item)[0]
        data.append(link)
        name=re.findall(find_name,item)[0]
        data.append(name)
        intro=re.findall(find_intro,item)[0]
        data_list.append(data)
    return data_list

def ask_data(url_base):
    headers={"User-Agent": "Mozilla / 5.0(Windows NT 10.0; Win64; x64) AppleWebKit / 537.36(KHTML, like Gecko) Chrome / 80.0.3987.122  Safari / 537.36"}
    r=requests.get(url_base,headers=headers)
    try:
        html=r.content.decode('utf-8')
    except:
        print('爬取失败')
    return html

def savedata(data_list,path):
    book = xlwt.Workbook(encoding="utf-8", style_compression=0)
    sheet=book.add_sheet('教师信息',cell_overwrite_ok=True)
    col=['信息链接','教师姓名','教师简介']
    for i in range(0,3):
        sheet.write(0,i,col[i])
        for i in range(0,41):
            print("第%d条" % (i + 1))
            data = data_list[i]
            for j in range(0,3):
                sheet.write(i + 1, j, data[j])
    book.save(path)


if __name__ == '__main__':
    url_base='http://xmtxy.xjtu.edu.cn/szdw/zzjs.htm'
    main()
    url_base='http://xmtxy.xjtu.edu.cn/szdw/zzjs/1.htm'
    main()
    print('爬取完毕')

我刚看了一下，应该是正则表达式的问题，好像没有匹配到字符串

Answer 1

soup.find_all('ul', style='overflow:hidden;')
style没有下划线，你加了当然找不到，既然用了bs4还用正则干嘛。
初学最好还是养成写注释的习惯