select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=1
select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=2
select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=3
select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=4
select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number>=5
如何把这5条sql语句变成一条,我要的结果是 =1=2=3=4大于5的用户分别说多少,不是要总数的亲们
sql语句问题求大神帮忙帮忙
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- feiyun0112 2014-06-18 07:02关注
select
A=(select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=1)
,B=(select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=2)
,C=(select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=3)
,D=(select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number=4)
,E=(select count(*) from (SELECT HY_GUID,COUNT(*) number FROM dbo.BI_GYDD GROUP BY HY_GUID) a where number>=5)解决 无用评论 打赏 举报
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