m0_38034574 2019-02-03 12:45 采纳率: 0%
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已结题

原生JS代码计时，为什么秒数不随时间刷新？

<!DOCTYPE html>



day25-27(1)

var d = new Date(); var res = document.getElementById("result"); var t; function time() { var year = d.getFullYear(); var month = d.getMonth()+1; var day = d.getDate(); var weekday = ["星期一","星期二","星期三","星期四","星期五","星期六","星期日"]; var week = d.getUTCDay()+1; var hour = d.getHours(); var minutes = d.getMinutes(); var seconds = d.getSeconds(); minutes = checkTime(minutes); seconds = checkTime(seconds); res.innerHTML = year + "年" + month + "月" + day + "日"+ " " + weekday[week] + " " + hour + ":" + minutes + ":" + seconds; console.log(seconds); t = setTimeout(time, 1000); } function checkTime(i) { if (i<10) {i="0" + i} return i } time();


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3条回答 默认 最新

  • esunf 2019-02-10 19:35
    关注
    <!doctype html>
<html lang="en">
<head>
    <meta charset="UTF-8" />
    <title>sort</title>
</head>
<body>
<span id="result"></span>
</body>
<script>

var res = document.getElementById("result");

function time() {
    var d = new Date();
    var year = d.getFullYear();
    var month = d.getMonth() + 1;
    var day = d.getDate();
    var weekday =  ["星期一","星期二","星期三","星期四","星期五","星期六","星期日"]; 
    var week = d.getUTCDay() + 1;
    var hour = d.getHours();
    var minutes = d.getMinutes();
    var seconds = d.getSeconds();
    minutes = ('0' + minutes).slice(-2);
    seconds = ('0' + seconds).slice(-2);
    res.innerHTML =  year + "年" + month + "月" + day + "日"+ " " + weekday[week] + " " + hour + ":" + minutes + ":" + seconds;
    setTimeout(time, 1000); 
} 

time();

</script>
</html>
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