php正则表达式匹配出想要的结果

Question

如何写才能把

第一集#https://iqiyi.cdn9-okzy.com/20201104/43645634255.html
第二集#https://iqiyi.cdn9-okzy.com/20201104/75676457567.html

正则匹配出#的前后生成

<a src="https://iqiyi.cdn9-okzy.com/20201104/43645634255.html">第一集</a>
<a src="https://iqiyi.cdn9-okzy.com/20201104/75676457567.html">第二集</a>

类似

$content = preg_replace("第一集#https://iqiyi.cdn9-okzy.com/20201104/43645634255.html", '<a src="$1">$2</a>\n', $content);

昨天试了一天没成功

Answer 1

$content="第一集#https://iqiyi.cdn9-okzy.com/20201104/43645634255.html

第二集#https://iqiyi.cdn9-okzy.com/20201104/75676457567.html";
echo $content = preg_replace("/(.*?)\#(.*?)/iU", '<a src="$2">$1</a><br>', $content);