最近遇到了项目遇到了这样的问题,如下所示爬虫爬取下一页的内容,求各位解决解决
4条回答 默认 最新
CSDN专家-showbo 2021-08-20 20:46关注直接请求数据接口就行了,分页参数是pn,这修改就行,示例代码如下,有帮助麻烦点个采纳【本回答右上角】,谢谢~~有其他问题可以继续交流~
http://3.push2.eastmoney.com/api/qt/clist/get?cb=jQuery1124032332843249790666_1629461999400&pn={}&pz=20&po=1&np=1&ut=bd1d9ddb04089700cf9c27f6f7426281&fltt=2&invt=2&fid=f3&fs=m:1+t:2,m:1+t:23&fields=f1,f2,f3,f4,f5,f6,f7,f8,f9,f10,f12,f13,f14,f15,f16,f17,f18,f20,f21,f23,f24,f25,f22,f11,f62,f128,f136,f115,f152&_=1629461999333
数据对照

import requests url="http://3.push2.eastmoney.com/api/qt/clist/get?pn={}&pz=20&po=1&np=1&ut=bd1d9ddb04089700cf9c27f6f7426281&fltt=2&invt=2&fid=f3&fs=m:1+t:2,m:1+t:23&fields=f1,f2,f3,f4,f5,f6,f7,f8,f9,f10,f12,f13,f14,f15,f16,f17,f18,f20,f21,f23,f24,f25,f22,f11,f62,f128,f136,f115,f152&_=1629461999333" headers={ "User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/92.0.4515.159 Safari/537.36" , "Referer":"http://quote.eastmoney.com/center/gridlist.html" } for i in range(1,3):#采集前2页 rurl=url.format(i) r=requests.get(rurl,headers=headers) data=r.json() for item in data['data']['diff']: print('代码:%s\t名称:%s\t最新价:%s\t涨跌幅:%s'%(item['f12'],item['f14'],item['f2'],item['f3']))本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 3无用