c语言练习求大家解答

Question

y = 1; (x <= 1)
y = x; (x >1 && x < 10)
y = 2x+1;(x >= 10)
终端输入x值，编程实现求解该函数的值。

Answer 1

#include<stdio.h>
int main(){
    int x;
    scanf("%d",&x);
    if(x<=1)printf("y=1");
    else if(x>1&&x<10)printf("y=%d",x);
    else if(x>=10)printf("y=%d",x*2+1);
}