这又哪里错了？意图为求ax2+bx+c的两个根

Question

Answer 1

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你看看我的吧：

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main()
{
    float a, b, c ;
    printf("Input a ,b , c :");
    scanf("%f%f%f",&a,&b,&c);
    if(fabs(a)<=1e-15)    //条件：当|a|<0 时  可以改成<=EPS
    {                     //1e-15  表示一个极小的数  浮点型零就是一个近似值
        printf("不是一元二次方程");
        printf("x = %.2f",c/b);
        exit(0);              //执行到此处 程序返回0 并退出
    }
    else
    {
        float disc , p ,q , x1 ,x2 ;
        disc = b*b - 4*a*c;
        p = -b/(2*a)  ;
        q = sqrt(fabs(disc))/(2*a) ;
        if(fabs(disc)<=1e-15)
        {
            printf("x1 = x2 = %.2f",p);
        }
        else if(disc >1e-15)
        {
            printf("x1 = %.2f, x2 = %.2f",p+q,p-q);
        }
        else  //(德尔塔小于0 )
        {
            printf("x1 = %.2f+%.2fi\n",p,q);
            printf("x1 = %.2f-%.2fi\n",p,q);
        }

    }
    return 0;
}

或者是：

#include<stdio.h>
#include <math.h>
#define EXP 0.0000001
int main()
{
    double a = 0.0, b = 0.0, c = 0.0;
    printf("please enter value of a,b,c:");
    scanf("%lf%lf%lf", &a, &b, &c);
    if (a > -EXP && a < EXP)
    {
        printf("the formula is fales\n");
    }
    else
    {
        double disc = b * b - 4 * a * c;
        if (disc > -EXP && disc < EXP)
        {
            printf("the only explain is:%lf\n", ((-b + sqrt(disc)) / (2 * a)));
        }
        else if (disc > 0)
        {
        printf("two explain is:%lf %lf\n", ((-b + sqrt(disc)) / (2 * a)), ((-b - sqrt(disc)) / (2 * a)));
        }
        else
        {
        printf("no explain");
        }
   }
    return 0;
}