pat乙级 1031查验身份证

Question

#include
using namespace std;
#include
int main()
{
int n;
cin >> n;
int quanzhong[17] = { 7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2 };
char xiaoyan[11] = { '1','0','x','9','8','7','6','5','4','3','2' };
int cnt = 0;
for (int i = 1; i <= n; i++)
{
int sum = 0;
int flag = 1;
char id[18];
scanf("%s",id);
for (int i = 0; i < 17; i++)
{
if (!(id[i] >= '0'&&id[i] <= '9'))
{
cout << id << endl;
cnt++;

            flag = 0;
            break;
        }
    }
    if (flag == 1)
    {
        for (int j = 0; j < 17; j++)
        {
            sum = sum + (id[j] - '0')*quanzhong[j];
        }
        if (xiaoyan[sum % 11] != id[17])
        {
            cout << id << endl;
            cnt++;
        }
    }
}
if (cnt == 0)
{
    cout << "All passed" << endl;
}
system("pause");
return 0;

}

为什么这样会部分正确，网上有个答案跟我基本一样但是全部正确

Answer 1

行了跑过了
原文校验码是大写的X,你匹配用的是小写的x,所以有的点通不过
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