代码异或运算部分运行出错，编译没有问题

Question

题设是寻找数组中只出现一次的数，其他数字均出现两次（力扣初级算法的题）

代码如下

#include<stdlib.h>
int* array(int numsSize);
int singleNumber(int* nums, int numsSize);
 int main()
 {
     int numsSize;
    scanf("%d",&numsSize); 
    int* nums; 
    nums = array(numsSize);
    int single  = 0;
    single = singleNumber(nums,numsSize);
    printf("只出现一次的是：%d",single);
    free(nums);
    return 0;
  } 
  int singleNumber(int* nums, int numsSize){
    int ans = 0;
    for(int i = 0; i < numsSize; i++){
        ans ^= nums[i];**//debug运行到这一步出错Segmentation Fault**
    }
    return ans;
}
int* array(int numsSize)//返回一个动态数组 
 {
     int* p = (int*)malloc(sizeof(int)*numsSize);
    if (p == NULL)
    {
        printf("未申请到内存");
        return 0;
    }
     for(int i = 0;i <numsSize;i++)
     {
         scanf("%d",&p[i]);
    }
}

Answer 1

#include<cstdlib>
#include <cstdio>
#include <iostream>
using namespace std;
int* array(int numsSize);
int singleNumber(int* nums, int numsSize);
 int main()
 {
     int numsSize;
    scanf("%d",&numsSize); 
    int* nums; 
    nums = array(numsSize);
    int single  = 0;
    single = singleNumber(nums,numsSize);
    printf("只出现一次的是：%d",single);
    free(nums);
    return 0;
  } 
  int singleNumber(int* nums, int numsSize){
    int ans = 0;
    for(int i = 0; i < numsSize; i++){
        ans ^= nums[i];//debug运行到这一步出错Segmentation Fault**
    }
    return ans;
}
int* array(int numsSize)//返回一个动态数组 
 {
     int* p = (int*)malloc(sizeof(int)*numsSize);
    if (p == NULL)
    {
        printf("未申请到内存");
        return 0;
    }
     for(int i = 0;i <numsSize;i++)
     {
         scanf("%d",&p[i]);
    }
    return p;
}