如何使用python解决英语随机替换密码问题?

Question

有一段用随机替代密码加密的密文(如 a-k,b-t 不是简单的轮换), 我看了有用词典匹配或者单词出现频率来解密的方法,但是词典匹配好像不适用单词之间不空格的情况,有没有大神给个思路....拜谢

文本如下

ejitpspawaqlejitaiulrtwllrflrllaoatwsqqjatgackthlsiraoa
twlplqjatwjufrhlhutsqataqitatsaittkstqfjcae

Answer 1

-*- coding:utf-8

import random

随机生成密码

def RandomPasswd( rang=None):
numlist = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'q', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D',
'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'W', 'R', 'S', 'T', 'U', 'V', 'W', 'X',
'Y', 'Z']
if rang == None:
_Passwd = "".join(random.choice(numlist) for i in range(8))
else:
Passwd = "".join(random.choice(_numlist) for i in range(int(rang)))
return _Passwd

print(RandomPasswd())

-*- coding:utf-8

import random

随机生成密码

def RandomPasswd( rang=None):
numlist = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'q', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D',
'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'W', 'R', 'S', 'T', 'U', 'V', 'W', 'X',
'Y', 'Z']
if rang == None:
_Passwd = "".join(random.choice(numlist) for i in range(8))
else:
Passwd = "".join(random.choice(_numlist) for i in range(int(rang)))
return _Passwd

print(RandomPasswd())
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