C语言用malloc申请19844*19844二维数组，写入位置冲突

Question

double** kk1;
kk1 = (double**)malloc(sizeof(double*) * 19844);
for (int i = 0; i < 19844; ++i)
{
kk1[i] = (double*)malloc(sizeof(double) * 19844);
}
if (kk1 == NULL)
{
printf("error");
}
for (int i = 0; i < 19844; i++)
{
for (int j = 0; j < 19844; j++)
{
kk1[i][j] = 0;
}
}
printf("%lf", kk1[0][0]);
}
请指教！！感谢

Answer 1

for (int i = 0; i < 19844; ++i)
{
kk1[i] = (double*)malloc(sizeof(double) * 19844);
}

二维数组空间不是分配好了，你这循环分配，怎么可能够用啊
你要想都赋值为0，可以用memset啊