Java语言流程控制阶乘计算

Question

Java语言
计算多项式1!+2!+3!+...+n!,当多项式之和超过10000时停止，输出累加之和以及n的值

Answer 1

代码如下,有帮助望采纳

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        int a = 0;
        int s = 1;
        while (a < 10000) {
            a += addN(s++);
            // System.out.println(a);
        }
        System.out.println(a);
        System.out.println(s - 1);

    }

    public static int addN(int x) {
        int a = 1;
        for (int i = 1; i <= x; i++) {
            a *= i;
        }
        return a;
    }
}

Answer 2

int sum = 0;
int t = 1;
for(int n = 1;sum <= 10000;n++){
t *= n;
sum += t;
}
System.out.println("sum="+sum+",n=" + n);