程序while第一个循环执行不了怎么回事

Question

#include <stdio.h>
int main(){
int a,c,e,h,x,v,z;
int g = 0;
int b = 1;
int d;
int y = 1;
int f = 10;
scanf("%d",&a);// 个数
while(a >= b){
scanf("%d",&c);
if (c == 0){
printf("0");
}
else{
for (d=1;d<=c;d*=10) {
//e = c / d % f;
g+=1;
//printf("%d ",g);
}
}
h = g;
g = 0;
for (x = 1;x<h;x++){
y = y * 10;
//printf("%d ",y);
}
for (z = 1;z <= h;y /= 10){
v = c / y % f;
printf("%d ",v);
}

    b+=1;
    //printf("%d\n",b);
}
return 0;

}

Answer 1

修改如下，供参考：

#include <stdio.h>
int main() {
    int a, c, e, h, x, v, z;
    int g = 0;
    int b = 1;
    int d;
    int y = 1;
    int f = 10;
    scanf("%d", &a);// 个数
    while (a >= b) {
        scanf("%d", &c);
        if (c == 0) {
            printf("0");
        }
        else {
            for (d = 1; d <= c; d *= 10) {
                //e = c / d % f;
                g += 1;
                //printf("%d ",g);
            }
        }
        h = g;
        //g = 0;      //修改
        for (x = 1; x < h; x++) {
            y = y * 10;
            //printf("%d ",y);
        }
        for (z = 1; z <= h; y /= 10,z++) {  //修改
            v = c / y % f;
            printf("%d ", v);
        }
        g = 0;     //修改
        y = 1;      //修改 
        b += 1;
        //printf("%d\n",b);
    }
    return 0;
}