C语言问题 打印命令行参数问题，球帮，蟹蟹

Question

请问这个应该怎么做？第一张是原题，第二张是机翻。请帮我编写1下，蟹蟹。

Answer 1

代码如下,
有帮助望采纳

#include <stdio.h>
int main(int argc, char const *argv[])
{
    printf("Program name: %s\n", argv[0]);
    if (argc == 1)
        printf("There are no other arguments");
    else
    {
        printf("There are %d arguments", argc - 1);
        for (int i = 1; i < argc; i++)
        {
            printf("\tArgument %d is \"%s\"\n", i, argv[i]);
        }
    }
    return 0;
}