
3条回答 默认 最新
神仙别闹 2021-09-29 17:39关注此代码适用于MS SQL Server
SELECT d.dept_id AS '部门编号', d.dept_name AS '部门名称', (SELECT COUNT(*) FROM employee WHERE dept_id=d.dept_id AND emp_wage BETWEEN 0 AND 4999) AS '5K以下员工人数', (SELECT SUM(emp_wage) FROM employee WHERE dept_id=d.dept_id AND BETWEEN 0 AND 4999) AS '5K以下薪酬小计', (SELECT COUNT(*) FROM employee WHERE dept_id=d.dept_id AND emp_wage BETWEEN 5000 AND 10000) AS '5K-10K员工人数', (SELECT SUM(emp_wage) FROM employee WHERE dept_id=d.dept_id AND emp_wage BETWEEN 5000 AND 10000) AS '5K-10K薪酬小计', (SELECT COUNT(*) FROM employee WHERE dept_id=d.dept_id AND emp_wage>10000) AS '10K以上员工人数', (SELECT SUM(emp_wage) FROM employee WHERE dept_id=d.dept_id AND emp_wage >10000) AS '10K以上薪酬小计', (SELECT COUNT(*) FROM employee WHERE dept_id=d.dept_id) AS '部门员工人数总数', (SELECT SUM(emp_wage) FROM employee WHERE dept_id=d.dept_id) AS '部门薪酬合计', (SELECT AVG(emp_wage) FROM employee WHERE dept_id=d.dept_id) AS '部门薪酬均值', (SELECT MAX(emp_wage) FROM employee WHERE dept_id=d.dept_id) AS '部门薪酬最大值', (SELECT MIN(emp_wage) FROM employee WHERE dept_id=d.dept_id) AS '部门薪酬最小值' FROM department AS d ORDER BY d.dept_id ASC本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 1无用