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闯入秋 2021-09-30 11:39关注#include<stdio.h>
int main(int argc,char**argv){
char num[5];
int result[5];
int sum = 0;
scanf("%c,%c,%c,%c,%c",&num[0],&num[1],&num[2],&num[3],&num[4]);
for(int i = 0;i<5;i++){
if(num[i] == 'A')
result[i] = 1;
else if(num[i] == 'B')
result[i] = 2;
else if(num[i] == 'C')
result[i] = 3;
else if(num[i] == 'D')
result[i] = 4;
else
result[i] = 0;
sum+=result[i];
}
printf("%d\n",sum);
return 0;
}本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 1无用