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技术专家团-Joel 2021-10-03 00:25关注你好!可以这样
i = 3; while(i<=size(s,2)) j = 2; while(j<=size(s,1)) total(j-1) = total(j-1) + s{j,i}; j = j+1; end i = i+1; end本回答被题主选为最佳回答 , 对您是否有帮助呢?解决评论 打赏 举报无用 2
你好!可以这样
i = 3;
while(i<=size(s,2))
j = 2;
while(j<=size(s,1))
total(j-1) = total(j-1) + s{j,i};
j = j+1;
end
i = i+1;
end