vue前端接收springboot拦截器返回的错误信息并进行处理

Question

设计一个单态登录的功能，在拦截器处对sessionId进行了校验，如果已在其他设备登录会返回错误信息，但是vue前端怎么接收这个错误信息并根据错误信息进行踢人下线呢
public class JwtIntercepter implements HandlerInterceptor {
private AuthenticationCheck AuthticationCheck;

@Override
public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception {
    if("OPTIONS".equals(request.getMethod().toUpperCase())){
        return true;
    }
    String token = request.getHeader("token");
    Map map = new HashMap();
    try {
        JwtUtils jwtUtils = new JwtUtils();
        jwtUtils.verify(token);
        AuthticationCheck.getToken(token);
        try{
            LoginListener loginListener = new LoginListener();
            loginListener.checkSessionId(token);
        }catch (Exception e){
            e.printStackTrace();
            map.put("msg",e.getMessage());
            String json = new ObjectMapper().writeValueAsString(map);
            response.setContentType("application/json;charset=UTF-8");
            response.getWriter().println(json);
            return false;
        }
        System.out.println("拦截器role"+jwtUtils.getRole(request));
        return true;
    }catch (SignatureVerificationException e){
        e.printStackTrace();
        map.put("msg","无效签名");
    }catch (TokenExpiredException e){
        e.printStackTrace();
        map.put("msg","令牌过期");
    }catch (Exception e){
        e.printStackTrace();
        map.put("msg","令牌无效");
    }
    map.put("state",false);
    String json = new ObjectMapper().writeValueAsString(map);
    response.setContentType("application/json;charset=UTF-8");
    response.getWriter().println(json);
    return false;
}

}

Answer 1

要使用token技术实现，不能使用session。