输入一个整数n,计算 1+1/（1-3）+1/（1-3+5）+.+1/(1-3+5-.+2n-1)的值

Question

C初学

这哪错了

#include <stdio.h>{
int main()

int n,i,j,flag,fenmu;
double sum,item;
sum=0;
item=1;
flag=1;
fenmu=1;
scanf("%d",&n);
for(i=1;i<=n;i++)
    {
        for(j=1;j<=n;j+2)
        {
            flag=-flag;
            fenmu=fenmu+j*flag;
            item=1.0/fenmu;
        }
        sum=sum+item;
    }
    printf("%.2f\n",sum);
return 0;

}

Answer 1

修改后如下:
有帮助望采纳~

#include <stdio.h>
int main()
{
    int n, i, j, flag, fenmu;
    double sum, item;
    sum = 0;
    item = 1;
    flag = 1;
    fenmu = 1;
    scanf("%d", &n);
    for (i = 1; i <= n; i++)
    {
        for (j = 1; j <= n; j += 2)
        {
            flag = -flag;
            fenmu = fenmu + j * flag;
            item = 1.0 / fenmu;
            //printf("debug\n");
        }
        sum = sum + item;
    }
    printf("%.2f\n", sum);
    return 0;
}