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qzjhjxj 2021-10-06 10:31关注修改如下,供参考:
#include <stdio.h> #include <math.h> #define N 20 double shulie(int n) { int s[N] = { 0 }, i; double r1; s[0] = 0; s[1] = 0; s[2] = 1; for (i = 3; i < n; i++) { s[i] = s[i - 1] + s[i - 2] + s[i - 3]; } r1 = 0; for (i = 0; i < n; i++) { r1 += sqrt((double)s[i]); } return r1; } int main() { int n; double r; scanf("%d", &n); r = shulie(n); printf("%f", r); return 0; }本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报