构建月净收入函数
#净收入 = 月薪 - 五险一金 + 奖金 - 个人所得税
def final_income (s,b_avg):
df_i = pd.DataFrame ({
'月薪' : [s for i in range (120)],
'五险一金': [insurance (s) for i in range (120)],
'奖金' : bonus (b_avg)
})
df_i['计税部分'] = df_i ['月薪'] + df_i ['奖金']
df_i['个人所得税'] = df_i ['计税部分']. apply(lambda x: tax(x))
df_i['净收入'] = df_i ['月薪'] + df_i ['奖金'] + df_i ['五险一金'] - df_i ['个人所得税']
return df_i
result = final_income (10000,1500)
result()
这个是我打的代码,但是提示我float is not callable, 自己尝试调试,发现result = final_income (10000,1500) 以上的代码都是正确的, 有没有大佬帮忙指点一下迷津,怎么处理
def tax (salary_sum):
if salary_sum <= 3500:
return 0
elif salary_sum <= (3500+1500):
return (salary_sum - 3500) * 0.03
elif salary_sum <= (3500 + 1500 +3000):
return 1500 * 0.03 + (salary_sum- 1500 - 3500) * 0.1
elif salary_sum <= (3500 + 1500 + 3000 + 4500):
return 1500 * 0.03 + 3000 * 0.1 + (salary_sum - 1500-3500-3000) * 0.2
elif salary_sum <= (3500 + 1500 + 3000 + 4500 + 26000):
return 1500 * 0.03 + 3000 * 0.1 + 4500 * 0.2 + (salary_sum - 1500-3500-3000-4500) * 0.3
elif salary_sum <= (3500 + 1500 + 3000 + 4500 + 26000 + 20000) :
return 1500 * 0.03 + 3000 * 0.1 + 4500 * 0.2 + 26000 * 0.25 + (salary_sum - 1500 - 3500 - 3000 - 4500 - 26000) * 0.3
elif salary_sum <= (3500 + 1500 + 3000 + 4500 + 26000 + 20000 + 25000) :
return 1500 * 0.03 + 3000 * 0.1 + 4500 * 0.2 + 26000 * 0.25 + 20000 * 0.3 + (salary_sum - 1500 - 3500 - 3000 - 4500 - 26000 - 20000) * 0.35
else:
return 1500 * 0.03 + 3000 * 0.1 + 4500 * 0.2 + 26000 * 0.25 + 20000 * 0.3 + 25000 * 0.35 + (salary_sum - 1500 - 3500 - 3000 - 4500 - 26000 - 20000- 25000) * 0.45
test =48016
print ('函数构建完成, 当月薪为%.1f元时, 需要缴纳税费%.2f元'%(test, tax(test)))
#魔法函数,为什么不能用
# salary_sum = 10000
# tax = tax (salary_sum)
# print ('工资为 '+ str (salary_sum), '税费为' + str(tax)