计算问题输出一直是0

Question

#include<stdio.h>
int main()
{
double m,t;
scanf("%d",&m);
int n;
n=(int)(m/100000);
if(n>10)
t=39500.0+(m-1000000)0.01;
switch(n)
{
case 0:
t=m0.1;
break;
case 1:
t=10000.0+(m-100000)*0.075;
break;
case 2:
case 3:
t=17500.0+(m-200000)*0.05;
break;
case 4:
case 5:
t=27500.0+(m-400000)*0.03;
break;
case 6:
case 7:
case 8:
case 9:
t=33500.0+(m-600000)*0.015;
break;
}
printf("%.2f",t);
return 0;
}

Answer 1

贴代码，代码都不全，代码别发截图