计算式子的值并显示在屏幕上

Question

Answer 1

#include <stdio.h>
int main()
{
    int n,i;
    long long s = 0;
    scanf("%d",&n);
    for (i=1;i<=2*n;i++)
    {
        if(i%2==0)
            s += i*i*i;
        else
            s += i*i;
    }
    printf("%lld",s);
    return 0;
}