一直显示在形参表中不匹配啥情况啊，我晕了，vs2019

Question

//自己的通用的数组类
#pragma once
#include<iostream>
using namespace std;
template<class T>
class MyArray
{
public:
    MyArray(int capacity)
    {
        cout << "MyArray的有参构造调用" << endl;
        this->m_Capacity = capacity;
        this->m_Size = 0;
        this->pAddress = new T[this->m_Capacity];
    }
    MyArray(const MyArray& arr)
    {
        count << "MyArry的拷贝构造调用" << endl;
        this->m_Capacity = arr.m_Capacity;
        this->m_Size = arr.m_Size;
        this->pAddress=new T[arr.m_Capacity];
        for (int i = 0; i < this->m_Size; i++)
        {
            this->pAddress[i] = arr.pAddress[i];
        }
    }
    MyArray&operator=(const MyArray & arr)
    {
        cout << "MyArry的operator=的调用" << endl;
        if (this->pAddress != NULL)
        {
            delete[] this->pAddress;
            this->pAddress = NULL;
            this->m_Capacity = 0;
            this->m_Size = 0;
        }
        this->m_Capacity = arr.m_Capacity;
        this->m_Size = arr.m_Size;
        this->pAddress=new T[arr.m_Capacity];
        for (int i = 0; i < this->m_Size; i++)
        {
            this->pAddress[i] = arr.pAddress[i];
        }
        return *this;
    }
    ~MyArray()
    {
        if (this->pAddress != NULL)
        {
            cout << "析构函数调用" << endl;
            delete[] this->pAddress;
            this->pAddress = NULL;
        }
    }
private:
    T * pAddress;//指针指向堆区开辟的真实数组
    int m_Capacity;//容量
    int m_Size;//大小
};

Answer 1

拷贝构造函数中
this->m_Capacity = arr.m_Capacity;
这么写不行啊。成员变量都是私有的，arr.m_Capacity这么访问不可以。要加get函数