c# json 串解析问题

Question

收到接口返回的 json 串：

{"code":0,"msg":"","data":{"sp000998":{"qfqday":[["2021-09-27","5.850","5.610","5.910","5.560","305300.000"],["2021-09-28","5.570","5.710","5.740","5.540","200538.000"],["2021-09-29","5.680","5.640","5.780","5.610","211602.000"],["2021-09-30","5.620","5.710","5.770","5.620","185429.000"],["2021-10-08","5.900","5.850","6.220","5.790","520652.000"]],"qt":{"sz000598":["51","\u5174\u84c9\u73af\u5883","000598","5.85","5.71","5.90","520652","243576","277076","5.84","1278","5.83","652","5.82","1564","5.81","604","5.80","1178","5.85","589","5.86","822","5.87","844","5.88","1146","5.89","877","","20211008161403","0.14","2.45","6.22","5.79","5.85/520652/312552254","520652","31255","1.74","13.01","","6.22","5.79","7.53","174.69","174.69","1.38","6.28","5.14","2.14","998","6.00","12.34","13.45","","","0.36","31255.2254","0.0000","0"," ","GP-A","24.44","0.17","1.70","10.59","4.21","6.22","4.36","4.84","5.41","14.48","2986218750","2986218750","10.45","23.91","2986218750"],"market":["2021-10-10 20:13:01|HK_close_\u5df2\u4f11\u5e02|SH_close_\u5df2\u4f11\u5e02|SZ_close_\u5df2\u4f11\u5e02|US_close_\u5df2\u4f11\u5e02|SQ_close_\u5df2\u4f11\u5e02|DS_close_\u5df2\u4f11\u5e02|ZS_close_\u5df2\u4f11\u5e02|NEWSH_close_\u5df2\u4f11\u5e02|NEWSZ_close_\u5df2\u4f11\u5e02|NEWHK_close_\u5df2\u4f11\u5e02|NEWUS_close_\u5df2\u4f11\u5e02|REPO_close_\u5df2\u4f11\u5e02|UK_close_\u5df2\u4f11\u5e02|KCB_close_\u5df2\u4f11\u5e02|IT_close_\u5df2\u4f11\u5e02|MY_close_\u5df2\u4f11\u5e02|EU_close_\u5df2\u4f11\u5e02|AH_close_\u5df2\u4f11\u5e02|DE_close_\u5df2\u4f11\u5e02|JW_close_\u5df2\u4f11\u5e02|CYB_close_\u5df2\u4f11\u5e02|USA_close_\u5df2\u4f11\u5e02|USB_close_\u5df2\u4f11\u5e02"],"zjlx":["sz000598","0.00","0.00","0.00","0","0.00","0.00","0.00","0","0.00","0.00","0.00","\u5174\u84c9\u73af\u5883","20200701","20200701^0.00^0.00","20200630^0.00^0.00","20200629^0.00^0.00","20200624^0.00^0.00","0.00","0.00","20200701085013"]},"mx_price":{"mx":{"data":[],"timeline":[]},"price":{"data":[]}},"prec":"5.840","version":"17"}}}

其中我只想获得 data 中的 qfqday 部分并解析为实体泛型List
sp000998 是商品编码，每次返回不同的商品信息json.

"data":{"sp000998":{"qfqday":[["2021-09-27","5.850","5.610","5.910","5.560","305300.000"],["2021-09-28","5.570","5.710","5.740","5.540","200538.000"],["2021-09-29","5.680","5.640","5.780","5.610","211602.000"],["2021-09-30","5.620","5.710","5.770","5.620","185429.000"],["2021-10-08","5.900","5.850","6.220","5.790","520652.000"]]

假设创建了实体 product 如何赋值 ?
对应实体属性：日期、早晨价格、中午价格、下午价格、晚上价格、成交额 的 product 实体中。

请教下具体方法：

目前尝试了 JObject jo = JObject.Parse(json 字符串); 获得的大对象杂乱无章，不太明了如何直接获得 data 中的 qfqday 下 各行数据到实体中。

Answer 1

使用了，的确挺方便，但用到这层后就不知道该如何取这个list 了：

JToken data = jo["data"];

得到：
{"sz000598": {
"hfqday": [
[
"2021-09-30",
"101.095",
"102.714",
"103.793",
"101.095",
"185429.000"
],
[
"2021-10-08",
"106.132",
"105.232",
"111.888",
"104.153",
"520652.000"
]
],
"qt": {
"sz000598": [
"51",
"兴蓉环境",
"000598",
"5.85",
"5.71",
"5.90",
"520652",
"243576",
"277076",
"5.84",
"1278",
"5.83",
"652",
"5.82",
"1564",
"5.81",
"604",
"5.80",
"1178",
"5.85",
"589",
"5.86",
"822",
"5.87",
"844",
"5.88",
"1146",
"5.89",
"877",
"",
"20211008161403",
"0.14",
"2.45",
"6.22",
"5.79",
"5.85/520652/312552254",
"520652",
"31255",
"1.74",
"13.01",
"",
"6.22",
"5.79",
"7.53",
"174.69",
"174.69",
"1.38",
"6.28",
"5.14",
"2.14",
"998",
"6.00",
"12.34",
"13.45",
"",
"",
"0.36",
"31255.2254",
"0.0000",
"0",
" ",
"GP-A",
"24.44",
"0.17",
"1.70",
"10.59",
"4.21",
"6.22",
"4.36",
"4.84",
"5.41",
"14.48",
"2986218750",
"2986218750",
"10.45",
"23.91",
"2986218750"
],
"market": [
"2021-10-10 21:51:02|HK_close_已休市|SH_close_已休市|SZ_close_已休市|US_close_已休市|SQ_close_已休市|DS_close_已休市|ZS_close_已休市|NEWSH_close_已休市|NEWSZ_close_已休市|NEWHK_close_已休市|NEWUS_close_已休市|REPO_close_已休市|UK_close_已休市|KCB_close_已休市|IT_close_已休市|MY_close_已休市|EU_close_已休市|AH_close_已休市|DE_close_已休市|JW_close_已休市|CYB_close_已休市|USA_close_已休市|USB_close_已休市"
],
"zjlx": [
"sz000598",
"0.00",
"0.00",
"0.00",
"0",
"0.00",
"0.00",
"0.00",
"0",
"0.00",
"0.00",
"0.00",
"兴蓉环境",
"20200701",
"20200701^0.00^0.00",
"20200630^0.00^0.00",
"20200629^0.00^0.00",
"20200624^0.00^0.00",
"0.00",
"0.00",
"20200701085013"
]
},
"mx_price": {
"mx": {
"data": [],
"timeline": []
},
"price": {
"data": []
}
},
"prec": "101.455",
"version": "17"
}}

就不知道如何取我想要的 qfqday 部分 了。

Answer 2

通过楼上方法，是可以取到你想要的值通过[‘’][‘’]，但是这种情况，很多时候会因为没有值导致null报错，建议使用实体类或者结构体

Answer 3

jo["data"]["sz000598"]["hfqday"].AsJEnumerable()