temp_list[1,2,3,4,5],利用for循环,依次输出list/ tuple/ dict/set构造的值
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CSDN专家-HGJ 2021-10-11 16:13关注代码可以这么写:
temp_list = [1, 2, 3, 4, 5] new_list = [] new_tuple = () new_dict = {} new_set = set() for x in temp_list: new_list.append(x) new_tuple+=(x,) new_dict.update({f'{x}': x}) new_set.add(x) print(new_list) print(new_tuple) print(new_dict) print(new_set)本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 2无用