一个歇后语和程序的对照计算的算法问题的解决，怎么才能使用C程序的语言的设计的代码来计算的

Problem Description
Garfield enjoys learns idioms very much. There is an interesting kind of idiom of chinese, and we call it ”歇后语". Garfield has a list of this idioms, but the format is awful. Garfield is not very smart, you should use the program to help him to tidy up the idioms.
The standard formt of an idiom here is “A——B”, for example, “王婆卖瓜——自卖自夸". But now there are three awful situations you need to deal with:
1)sometimes there is a pair of chinese brackets in the expression to explain something, and you need to omit the brackets and contexts between them. For example, “麦场上挂马灯——照常（场）".

2)sometimes there are several Bs for the unique A, and two Bs are separated by chinese semicolons. You need to slip the idiom, for each B. For example, “麻布手中绣牡丹——配不上；不配".

3)sometimes the dash between A and B is took place by chinese comma, and you need to change them into dash. For example, “泥菩萨过河，自身难保".

But sometimes both the dash and the comma exit in the idiom, then we define it that the dash is just the separator for A and B.

Input
There is a integer N(1<N<10000) indicating the number of the list to deal. Then N lines follows, each line contain an idiom, and the length of every idiom isn’t beyond 200.

Output
Int first line, output the number of the list you get. Then put the result you calculate. You should sort the list according to the length of idioms, then the lexicographical places.

Hint
中间用到的标点符号，可以在题目中或者输入数据中复制

Sample Input
4
王婆卖瓜——自卖自夸
麦场上挂马灯——照常（场）
麻布手中绣牡丹——配不上；不配
泥菩萨过河，自身难保

Sample Output
5
麦场上挂马灯——照常
王婆卖瓜——自卖自夸
麻布手中绣牡丹——不配
泥菩萨过河——自身难保
麻布手中绣牡丹——配不上