select COUNT(distinct cs.id),COUNT(distinct fo.id),COUNT(distinct re.id),COUNT(distinct lo.id) from dh_project_saler ps
left join dh_crm_saleruser cs
on cs.saleropenid=ps.saleropenid
left join dh_crm_follow fo
on fo.saler_openid=ps.saleropenid
left join dh_crm_record re
on re.saler_open_id=ps.saleropenid
left join dh_crm_look lo
on lo.saler_openid=ps.saleropenid
where cs.createtime between '2021-09-26' and '2021-09-27'
and fo.operating_time between '2021-09-26' and '2021-09-27'
and re.operating_time between '2021-09-26' and '2021-09-27'
and lo.create_time between '2021-09-26' and '2021-09-27'
and ps.number='HJ000069'
当这样子去查询的时候,如果最后一个统计为0的时候,前面的所有count都等于0了,怎么解决啊