数组过滤求解,在不确定name,和date的情况下, 找到 name 相同,date相同的对象, 把其 commodity 的内容拼结,返回一个对象
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<script>
var arr =[
{name:'张三',commodity:'电视',date:'2020-10-1'},
{name:'张三',commodity:'洗衣机',date:'2020-10-1'},
{name:'张三',commodity:'手机',date:'2020-10-1'},
{name:'李四',commodity:'手机',date:'2020-10-1'},
{name:'张三',commodity:'电脑',date:'2020-10-5'},
{name:'王五',commodity:'电脑',date:'2020-10-5'},
{name:'李四',commodity:'手机',date:'2020-10-8'},
{name:'王五',commodity:'音响',date:'2020-10-8'},
{name:'王五',commodity:'手机',date:'2020-10-8'},
]
//在不确定name,和date的情况下, 找到 name 相同,date相同的对象, 把其 commodity 的内容拼结,返回一个对象
//返回结果示例:
arr=[
{name:'张三',commodity:'电视,洗衣机,手机',date:'2020-10-1',number:3},
{name:'李四',commodity:'手机',date:'2020-10-1',number:1},
{name:'张三',commodity:'电脑',date:'2020-10-5',number:1},
{name:'王五',commodity:'电脑',date:'2020-10-5',number:1},
{name:'李四',commodity:'手机',date:'2020-10-8',number:1},
{name:'王五',commodity:'音响,手机',date:'2020-10-8',number:2}
]
console.log(arr)
</script>
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