Java任务，又来了，帮帮忙啊

Question

一，测试ArrayList，KinkedList的get方法的性能差别。
二，使用ArrayList，LinkedList集合存储学生对象。
分别用年龄，身份证号对所有学生对象排序。
排序时分别使用List.sort方法和Collections.sort方法排序

Answer 1

第二题

package test;

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.List;

public class Student {
    private String name;
    private int age;
    private String idNum;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public String getIdNum() {
        return idNum;
    }

    public void setIdNum(String idNum) {
        this.idNum = idNum;
    }

    public Student(String name, int age, String idNum) {
        this.name = name;
        this.age = age;
        this.idNum = idNum;
    }

    @Override
    public String toString() {
        return "Student [name=" + name + ", age=" + age + ", idNum=" + idNum + "]";
    }

    public static void main(String[] args) {
        Student s1 = new Student("张三", 12, "8498491511");
        Student s2 = new Student("张三2", 55, "8498491511");
        Student s3 = new Student("张三3", 13, "8498491511");
        Student s4 = new Student("张三", 60, "8498491511");
        Student s5 = new Student("张三4", 88, "8498491511");
        Student s6 = new Student("张三5", 23, "8498491511");
        Student s7 = new Student("张三6", 26, "8498491511");
        Student s8 = new Student("张三7", 36, "8498491511");
        List<Student> l1 = new ArrayList<>();
        l1.add(s1);
        l1.add(s2);
        l1.add(s3);
        l1.add(s4);
        l1.add(s5);
        l1.add(s6);
        l1.add(s7);
        l1.add(s8);
        List<Student> l2 = new LinkedList<>();
        l2.add(s1);
        l2.add(s2);
        l2.add(s3);
        l2.add(s4);
        l2.add(s5);
        l2.add(s6);
        l2.add(s7);
        l2.add(s8);
        // 按照年龄排序
        l1.sort(Comparator.comparing(Student::getAge));
        l1.forEach(System.out::println);
        System.out.println();
        // 按身份证号
        l1.sort(Comparator.comparing(Student::getIdNum));
        l1.forEach(System.out::println);
        System.out.println();
        // 按照年龄排序
        Collections.sort(l2, Comparator.comparing(Student::getAge));
        l2.forEach(System.out::println);
        System.out.println();
        // 按身份证号
        Collections.sort(l2, Comparator.comparing(Student::getIdNum));
        l2.forEach(System.out::println);
        System.out.println();
    }
}