怎么让运行结果显示具体数字?

Question

#include<stdio.h>
int main() {
int a,b;
float c,d;
long e,f;
unsigned u,v;
char c1,c2;
scanf("％d％d",&a,&b);
scanf("％f％f",&c,&d);
scanf("％ld％ld",&e,&f);
scanf("％o％o",&u,&v);
scanf("％c％c",&c1,&c2);
printf("\n");
printf("a=％7d,b=％7d\n",a,b);
printf("c=％10.2f,d=％10.2f\n",c,d);
printf("e=％17ld,f=％17ld\n",e,f);
printf("u=％o,v=％o\n",u,v);
printf("c1=％c,c2=％c\n",c1,c2);
return 0;}

Answer 1

我不知道你怎么编译通过的，你这里的%号是中文的，下面的代码应该输出正常的：

#include<stdio.h>
int main()
{
        int a,b;
        float c,d;
        long e,f;
        unsigned u,v;
        char c1,c2;
        scanf("%d%d",&a,&b);
        scanf("%f%f",&c,&d);
        scanf("%ld%ld",&e,&f);
        scanf("%o%o",&u,&v);
        scanf("%c%c",&c1,&c2);
        printf("\n");
        printf("a=%7d,b=%7d\n",a,b);
        printf("c=%10.2f,d=%10.2f\n",c,d);
        printf("e=%17ld,f=%17ld\n",e,f);
        printf("u=%o,v=%o\n",u,v);
        printf("c1=%c,c2=%c\n",c1,c2);
        return 0;
}

结果：

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